Introduction to GAP – Exercise sheet 3

7th April 2025

Tutorial questions

  1. (Easy)

  2. (1)

    (*) Return all upper-triangular matrices of GL(3,q)\mathrm{GL}(3,q), for q2q\geq 2 a prime power. Check, for small qq, that this is a group of order q3(q1)3q^{3}(q-1)^{3}.

  3. (2)

    Compute a Sylow 22-subgroup of GL(3,5)\mathrm{GL}(3,5), and return all its abelian subgroups of exponent four.

  4. (Medium)

  5. (3)

    Show that GL(4,2)\mathrm{GL}(4,2) contains a subgroup isomorphic to SL(3,2)\mathrm{SL}(3,2).

    Hint: Look at the orders.

  6. (4)

    (*) Construct the holomorph of the elementary abelian group of order 2525. Recall that the holomorph of a group GG is the semidirect product of the group with its automorphism group.

  7. (Hard)

  8. (5)

    (*) Show the inner automorphism group of SL(2,7)\mathrm{SL}(2,7) is naturally a subgroup of the inner automorphism group of GL(2,7)\mathrm{GL}(2,7). Construct such an inclusion with GAP.

    Hint: Write the corresponding group diagrams, and look at the centres.

  9. (6)

    (*) Define the action of GL(n,q)\mathrm{GL}(n,q) on subspaces of its natural module (the vector space of dimension nn over the field of qq elements). Compute the corresponding stabilisers, up to conjugacy, in the case of n=3n=3 and q=4q=4. Does every subgroup of GL(3,4)\mathrm{GL}(3,4) arise as a stabiliser?

  10. (7)

    Construct the homomorphism Alt6Aut(Alt6)\operatorname{Alt}_{6}\to\operatorname{Aut}(\operatorname{Alt}_{6}), arising from the conjugation action.

    1. (a)

      Show that this map is injective, and its image is a normal subgroup.

    2. (b)

      Show that Aut(Alt6)/Alt6\operatorname{Aut}(\operatorname{Alt}_{6})/\operatorname{Alt}_{6} is isomorphic to C2×C2C_{2}\times C_{2}, the direct product of two cyclic groups of order two. Conclude that there must be exactly five non-trivial normal subgroups in Aut(Alt6)\operatorname{Aut}(\operatorname{Alt}_{6}), without using a subgroup function like NormalSubgroups to compute them.

      Hint: Use that Alt6\operatorname{Alt}_{6} is simple and the isomorphism theorems.

    3. (c)

      Show that there is a unique subgroup of Aut(Alt6)\operatorname{Aut}(\operatorname{Alt}_{6}) isomorphic to Sym6\operatorname{Sym}_{6}, and construct such a subgroup by looking at the image of the conjugation action homomorphism.

More exercises

  1. (8)

    Show that SL(3,7)\mathrm{SL}(3,7) has a unique non-trivial proper normal subgroup, and determine its structure. Do you recognise this subgroup?

  2. (9)

    Exhibit two non-equivalent transitive actions of SL(3,2)\mathrm{SL}(3,2) on a set of seven elements. Can you recognise these actions? Are there more?

  3. (10)

    Compute, up to conjugacy, the fixed subspaces of the order-22 elements in GL(3,4)\mathrm{GL}(3,4) acting on its natural module.

  4. (11)

    Write a function such that, given a subgroup HH of GL(n,q)\mathrm{GL}(n,q), it returns the list of HH-stable 22-dimensional subspaces. Evaluate this function for n=2n=2, 2q192\leq q\leq 19, and HH the Sylow pp-subgroup of GL(n,q)\mathrm{GL}(n,q), with pp the underlying characteristic.

  5. (12)

    Consider the group GL(3,q)\mathrm{GL}(3,q), for 2q92\leq q\leq 9.

    1. (a)

      Compute the subgroup UU of strictly upper-triangular matrices of GL(3,q)\mathrm{GL}(3,q) (with 11s along the diagonal). What can you say about this group?

    2. (b)

      Show that the normaliser of such a subgroup, say BB, is exactly the subgroup of upper-triangular matrices. This BB is called a Borel subgroup of GL(3,q)\mathrm{GL}(3,q).

    3. (c)

      Compute all subgroups of GL(3,q)\mathrm{GL}(3,q) containing BB. These are the parabolic subgroups of GL(3,q)\mathrm{GL}(3,q) containing BB.

    4. (d)

      Let pp be the underlying characteristic. Show that the previous family is in bijection with the pp-subgroups RR of UU for which the pp-core of the normaliser NGL(nq)(R)N_{\mathrm{GL}(n_{q})}(R) is exactly RR.

    5. (e)

      (Hard) Show that the previous bijection can be naturally made order-reversing.

  6. (13)

    Let H=GL(2,3)×GL(2,3)H=\mathrm{GL}(2,3)\times\mathrm{GL}(2,3) be embedded in GL(4,3)\mathrm{GL}(4,3) in the usual way by block matrices along the diagonal, and consider its natural action on the 44-dimensional vector space over the field of three elements, with the canonical basis given by e1,,e4e_{1},\ldots,e_{4}. Show that the only HH-invariant subspaces are 0, A=e1,e2A=\langle e_{1},e_{2}\rangle, B=e3,e4B=\langle e_{3},e_{4}\rangle, and ABA\oplus B.